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TS613 데이터시트 PDF




STMicroelectronics에서 제조한 전자 부품 TS613은 전자 산업 및 응용 분야에서
광범위하게 사용되는 반도체 소자입니다.


 

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부품번호 TS613 기능
기능 DUAL WIDE BAND OPERATIONAL AMPLIFIER WITH HIGH OUTPUT CURRENT
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TS613 데이터시트, 핀배열, 회로
TS613
DUAL WIDE BAND OPERATIONAL AMPLIFIER
WITH HIGH OUTPUT CURRENT
s LOW NOISE : 3nV/Hz, 1.2pA/Hz
s HIGH OUTPUT CURRENT : 200mA
s VERY LOW HARMONIC AND INTERMODU-
LATION DISTORTION
s HIGH SLEW RATE : 40V/µs
s SPECIFIED FOR 25LOAD
DESCRIPTION
The TS613 is a dual operational amplifier featur-
ing a high output current (200mA min.), large
gain-bandwidth product (130MHz) and capable of
driving a 25load with a 160mA output current at
±6V power supply.
This device is particularly intended for applications
where multiple carriers must be amplified simulta-
neously with very low intermodulation products.
The TS613 is housed in a SO8 package.
D
SO-8
(Plastic Micropackage)
PIN CONNECTIONS (top view)
APPLICATION
s UPSTREAM line driver for Assymetric Digital
Subscriber Line (ADSL) (NT).
ORDER CODE
Part Number Temperature Range
TS613ID
-40, +85°C
Package
D
D = Small Outline Package (SO) - also available in Tape & Reel (DT)
May 2000
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TS613 pdf, 반도체, 판매, 대치품
TS613
INTERMODULATION DISTORTION
The curves shown below are the measurements results of a single operator wired as an adder with a gain
of 15dB.
The operational amplifier is supplied by a symmetric ±6V and is loaded with 25.
Two synthesizers (Rhode & Schwartz SME) generate two frequencies (tones) (70 & 80kHz ; 180 &
280kHz).
An HP3585 spectrum analyzer measures the spurious level at different frequencies.
The curves are traced for different output levels (the value in the X ax is the value of each tone).
The output levels of the two tones are the same.
The generators and spectrum analyzer are phase locked to enhance measurement precision.
3rd ORDER INTERMODULATION
Gain=15dB, Vcc=±6V, RL=25, 2 tones 70kHz/
80kHz
3rd ORDER INTERMODULATION
Gain=15dB, Vcc=±6V, RL=25, 2 tones 180kHz/
280kHz
0
-10
-20
-30
-40
90kHz
-50
230kHz
-60
-70
-80
60kHz
-90
-100
220kHz
1 1,5 2 2,5 3 3,5 4 4,5
Vout peak (V)
2nd ORDER INTERMODULATION
Gain=15dB, Vcc=±6V, RL=25, 2 tones 180kHz/
280kHz, Spurious measurement @100kHz
0
-10
-20
-30
-40
-50
80kHz
-60
380kHz
-70
-80
640kHz
-90
740kHz
-100
1 1,5 2 2,5 3 3,5 4 4,5
Vout peak (V)
-55
-60
-65
-70
1,5 2 2,5 3 3,5 4 4,5
Vout peak (V)
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TS613 전자부품, 판매, 대치품
TS613
1µF capacitance provides a path for low frequen-
cies, the 10nF capacitance provides a path for
high end of the spectrum.
In differential mode the TS613 is able to deliver a
typical amplitude signal of 18V peak to peak.
The dynamic line impedance is 100. The typical
value of the amplitude signal required on the line
is up to 12.4V peak to peak. By using a 1:2 trans-
former ratio the reflected impedance back to the
primary will be a quarter (25) and therefore the
amplitude of the signal required with this imped-
ance will be the half (6.2 V peak to peak). Assum-
ing the 25series resistance (12.5for both out-
puts) necessary for impedance matching, the out-
put signal amplitude required is 12.4 V peak to
peak. This value is acceptable for the TS613. In
this case the load impedance is 25for each driv-
er.
For the ADSL upstream path, a lowpass filter is
absolutely necessary to cutoff the higher frequen-
cies from the DAC analog output. In this simple
non-inverting amplification configuration, it will be
easy to implement a Sallen-Key lowpass filter by
using the TS613. For ADSL over POTS, a maxi-
mum frequency of 135kHz is reached. For ADSL
over ISDN, the maximum frequency will be
276kHz.
INCREASING THE LINE LEVEL BY USING AN
ACTIVE IMPEDANCE MATCHING
With passive matching, the output signal ampli-
tude of the driver must be twice the amplitude on
the load. To go beyond this limitation an active
maching impedance can be used. With this tech-
nique it is possible to keep good impedance
matching with an amplitude on the load higher
than the half of the ouput driver amplitude. This
concept is shown in figure3 for a differential line.
Figure 3 : TS613 as a differential line driver with
an active impedance matching
100n
+12V
1k
Vi
47k
3 + 8 +12V
2_ 1
R2
R3
R1
R5
Vi 1 0µ 47k 100n
1k GND
100n
R4
6_
7
5 + GND
4
12.5
Vo°
Vo°
12.5
1µ
10n
1:2
Vo
Hybrid
25&
100Ω
Transformer
Vo
Component calculation:
Let us consider the equivalent circuit for a single
ended configuration, figure4.
Figure 4 : Single ended equivalent circuit
+
Vi _
1/2R1
R2
R3
Rs1
Vo°
-1
Vo
1/2RL
Let us consider the unloaded system. Assuming
the currents through R1, R2 and R3
as respectively:
2-R---V--1--i,
(--V-----i---–R----2-V----o---°----) a
n
d
(---V----i---+-----V----o----)
R3
As Vo° equals Vo without load, the gain in this
case becomes :
1 + -2---R----2-- + R----2--
G = V-----o---(---n---o----l--o---a----d---) = ------------R-----1------------R----3-
V i 1 R-----2-
R3
The gain, for the loaded system will be (1):
1 + -2---R----2-- + R----2--
GL
=
V-----o---(---w----i--t--h----l--o----a---d---)
Vi
=
1--
2
------------R-----1------------R----3-
1 R-----2-
,( 1
)
R3
As shown in figure5, this system is an ideal gener-
ator with a synthesized impedance as the internal
impedance of the system. From this, the output
voltage becomes:
V o = (V i G) (R oIout),(2)
with Ro the synthesized impedance and Iout the
output current. On the other hand Vo can be ex-
pressed as:
Vo
=
V i 1
+
2----R----2--
R1
+
RR-----23- 
----------------------------------------------
1 R-----2-
R3
R-----s--1----I---o---u----t
1 R-----2-
,(
3
)
R3
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